[pyrrole]

Say if there is an electron withdrawing group on an aromatic right. Will the protons that are ortho and para to it resonate at a slightly higher frequency than those that are meta to it. Because it is withdrawing electron density from those areas (ortho/para), right? and so the protons there will resonate at a higher frequency? And will this be true for both carbon and proton nmr?

[Honclbrif]

You could try checking out the SDBS or Aldrich library to further investigate this hypothesis.

Probably works best with 13C. The higher order coupling that occurs in monosubstituted phenyl rings makes ironing out individual protons in simple 1D spectra difficult/impossible.

[Vidya]

electron withdrawing group decreases electron density on o and p positions and these protons will be more deshielded  .Deshielding shifts the peak to downfield