I do not need an answer for the whole question, but just how to start it. Though I will write the whole question down:
A feed mixture consisting of 30% CO and 70% H2 is passed over a CuO-ZnO catalyst bed maintained at 500K what is the lowest operating pressure that would allow 40% conversion of the limiting reactant in the methanol synth reaction?
CO+2H -> CH OH
= -90 kJ/mole
= -25 kJ/mole
Assume Ideal gas and that is independent of T
Now my problem is setting up the question.
I believe the limiting reactant is CO because moles of H2 over moles of CO is 2 (using stoich values) and moles of H2 over moles of CO using the feed percentages (.7/.3) is 2.333 and since 2.33 is larger than 2 CO is the limiting reactant (page 120 of Elementary Principles of Chemical Processes / Rousseau).
I set up a chart with the initial feed, change and the final feed.
| CO | H2 | CH3COH | Total |
Initial | .3| | .7| | 0| | 1| |
Change | -.3x| | -.7x| | +x| | | |
Final | .3-.3x| | .7-.7x| | x| | 1| |
Something is wrong with the chart, and I believe it is the initial feed.
That's where I need the help. And what do I consider the conversion? Do I set x equal to 40%? or
equal to .40?
But after doing this, I can figure out the y (amount of each component), and then the K (equilibrium constant). Since $$ K = K_v \cdot K_p = K_y \cdot P^n /$$ and $$ K _v /$$ is 1 at Ideal gas, I can find that $$ K = P^n \cdot K_y /$$
I can figure out the rest using other equations for K since I have change of enthalpy and change of gibbs free energy.
But figuring out the beginning, ie K
y is the confusing part.