The Primary Equation in the original post is all about converting Cr3 to Cr6 . How ever it is not important part in calculation
I have done this
Cr207 + 6Fe+14 H= 2Cr+6Fe+7h2o.
Here Cr6 is converted to Cr3 , and Fe2 becomes Fe3 .
On calculation part
If I use 0.02 M Feso4 for the volumetric analysis and 30 ml is consumed
It would be 30*0.02 which would be 0.7 moles of chromate .
As per the Equation one mole of chromate will oxidize 6 moles of Fe2,so 6*0.7 =4.5 moles of Fe2 .
I have done till here .