I was wondering how to go about solving this particular question:
For mercury the enthalpy of vaporization is 58.51 kJ/mol and the entropy of vaporization is 92.92 J K^-1 mol^-1.
What is the normal boiling point of mercury?
Is the free energy for vaporization positive or negative below the boiling point?
I have no clue how to even start this one. Something to do with :delta:(G) = :delta:(H) - T :delta:(S) maybe?