[magicman]

In the preparation of a solution of sulfuric acid, 23.100g of SO3 was dissolved in enough water to prepare 1.300L of solution. What is the concentration of sulfur (moles per liter) in this solution?



SO3 + H20 --------> H2SO4

The equation is already balanced.

So far this is what ive got in my work, but i fear im making a mistake somewhere.

23.100 g H2SO4|  1 mol H2SO4  |1 mol S           | 1 g S
                         98.02g H2SO4 | 1 mol H2 SO 4 |

           

I know i should of used the liters by now, but i dont know where to use it.... Thanks in advance for the help.

[mike]

m = 23.100g

M = 80 g.mol-1

v = 1.300L

n = m/M = 23.100/80 = 0.289 moles of SO3/H2SO4/S


c = n/v = 0.289/1.300 = 0.222 mol.L-1

does this seem right?

[magicman]

i wouldnt know...what was your final answer ? how much Sulfurer?

[magicman]

actually i did. i see what u did, the calculations are right so i would assume yes your right thans.

[mike]

0.222mol.L-1