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Topic: entropy, spontaneous....  (Read 5198 times)

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Ice-cream

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entropy, spontaneous....
« on: September 30, 2005, 07:30:17 AM »
The melting point of water is 0 degrees C at 1atm pressure becuase under these conditions:
a) deltaS for the process H2O(s) --> H2O(l) is positive
b) deltaS and deltaS(surroundings) for the process H2O(s) --> H2O(l) are both positive
c) deltaS and deltaS(surroundings) for the process H2O(s) --> H2O(l) are equal in magnitude and opposite in sign
d) deltaG is positive for the process H2O(s)-->H2O(l)
e) none of these is correct

can anyone help me with this question.

GCT

  • Guest
Re:entropy, spontaneous....
« Reply #1 on: September 30, 2005, 12:02:47 PM »
equilibrium is attained at zero degrees, reversible, thus...I'm gonna go with c), since Ssys+Ssurr=0 for a reversible process (I'm actually on this chapter myself at the moment-P Chem?)

q/T+-q/T'=0

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