Hello!
Help me please
Present a lake as cylinder with the area of basis of 1,20 km
2 and in 210 meters high. Take into account, that the bottom of lake is formed a ferum(II) carbonate and carbon dioxide enters into lake at dissolution of FeCO
3. It is also known that water of epiphase of lake (50 meters) is unmixed with understrata; a temperature on a depth from 50 to 180 meters is approximately evened 23°c.
Calculate pH at the level of 50 and 180 meters. Such information is also known:
K
1(H
2CO
3)=3.57*10
-7K
2(H
2CO
3)=4.40*10
-11K
S(FeCO
3)=5.91*10
-11K
d(H
2CO
3)=0.0015