[quadsofdgods]

So i was studying alkyl halide prep reactions and came across this one

R-OH + HX  CH3X + H2O

HX coming from NaBr + H2SO4

I also have another reaction somewhere (some reaction) except using KBr instead of NaBr

Now my question is what would be the difference between using NaBr and KBr?
I`m guessing any differences are easily noted from the trends of alkali metals as you descend the group so K would be better to use than Na but the difference in reaction is very small so unless there are specific cases the difference could be ignored.
Am i correct?

[Schrödinger]

Since you are focusing on the preparation of an alkyl halide, this is something you need not turn your attention toward. But yeah, since replacing Na by K is not going to change the HX that is produced (HBr), I think it doesn't really make much of a difference which halide is used : KBr or NaBr. Maybe the yield is better with K, maybe it is better with Na.. It doesn't really matter much, at least not in this context.