[DQD]

The glass funnel, contains the solution with viscosity y (N.s/m²), radius r (mm), angle of bottom cone is 50^o, hole's diameter is d (mm) and flow coefficient C_v

with differential equation: -f_o.dH = C_v.f.w_o.dt
Caculate time solution's out of glass funnel

f_o: section of top the glass funnel
C_v : flow coefficient
f : section of hole
w : velocity through hole

I can't use integral from 2 sides equation to solve it, sb help me to get t(time) for caculating
and the viscosity, it dont be present at differential equation, why does it have in this problem ?

Sorry for my bad English and using speciality word

[SABRY]

Please review your differential equation. Take note following clues.

1. The velocity at the exit is given by following equation:
v = C_vSQRT(2gh)
The volume flowrate
dQ/dt = v x a
where a is the x-sectional area at the bottom. Cv, g and h I beleieve you can figure out

2. The incremental volume flow rate at any point h is given by:
dQ/dt = Adh/dt

where A is the x-sectional of the funnel and it varies with h. The radius r at any point is related to h by the angle 50^o.

3. Equation (1) and (2) should be equal.

4. Integrate to solve the equation

[SABRY]

Sorry... equation 2 should read

dQ/dt = - Adh/dt