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Topic: Henderson–Hasselbalch equation and Strong Base  (Read 1929 times)

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Offline TJ6900

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Henderson–Hasselbalch equation and Strong Base
« on: September 26, 2011, 11:59:07 PM »
I have a question in my class which I'm slightly confused on but I'm not going to give you the numbers and tell you guys to just do it for me.

The question says: "so many" mL of a Acetic Acid solution is added to "so many" mL NaOH solution. What is the final pH? And it gives the pKa value of acetic acid.

Simple enough except that Acetic Acid is the limiting reagent leaving unused NaOH in the solution. If I remember correctly: When a strong acid/base is in excess in the solution the H-H equation can not be used. Yet the question still gives a pKa value like it's relevant...

Any advice is greatly appreciated and if it helps, this is for an introductory Biochemistry class.

Thanks!

Offline Borek

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Re: Henderson–Hasselbalch equation and Strong Base
« Reply #1 on: September 27, 2011, 05:14:42 AM »
If you are sure about the stoichiometry, just ignore pKa.
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