[plasticfood]

            [d]    [e]     [f]
trail 1: .10M  .02M  .04M  10M/hr   
trail 2: .10M  .03M  .04M  15M/hr
trail 3: .20M  .02M  .08M  80M/hr
trail 4: .20M  .02M  .16M  160M/hr

i need help finding the order with respect to [d]. i know [e] and [f] is both 1st power, and i do know that [d] is second power. but how do i find [d] with no trails of [e] and [f] being the same?   

[Schrödinger]

In that case, since you have 3 variables (powers of d, e and f) you will need 3 distinct equations to solve for them. So you need 3 new trials with [d], [e] and [f] completely different everytime.

[plasticfood]

is there a more intuitive way of solving this? my teacher said something about, if you're using trail 1 and 3 to figure out power of [d], [e] remains constant and [f] doubled. i couldn't follow what happens after, but do you have any clue as to what he was saying?  

[sjb]

            [d]    [e]     [f]
trail 1: .10M  .02M  .04M  10M/hr   
trail 2: .10M  .03M  .04M  15M/hr
trail 3: .20M  .02M  .08M  80M/hr
trail 4: .20M  .02M  .16M  160M/hr

i need help finding the order with respect to [d]. i know [e] and [f] is both 1st power, and i do know that [d] is second power. but how do i find [d] with no trails of [e] and [f] being the same?   

If you know that [e] is first order (presumably from 1 and 2) and [f] is first order (from 3 and 4), you can perhaps create a trial 5, having [d]= 0.10M, [e]=0.02M, [f]=0.08M, and rate double that of trial 1, i.e 20M/hr, then compare this with 3 or similar?

[plasticfood]

i don't know if i did it right, but i set up the equation like this since i know the powers of e and f:


[.20]^x [.02]^1 [.08]^1 = 80
[.10]^x [.02]^1 [.04]^1 = 10

used algebra and solve for x, which i got 2. is this method legit?

[Schrödinger]

Yes this method is legit.