January 16, 2025, 07:12:05 AM
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Topic: Calculating Free Energy of a Reaction from Standard Entropy and Enthalpy of Form  (Read 1473 times)

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Offline mcduffels

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So I can't figure out what I'm doing wrong with this problem:

2NH3 -> N2 + 3H2

*This reaction is assuming independence from temperature

Enthalpy Entropy
NH3 -46.1 192.3
N2... 00.0 191.5
H2... 00.0 130.6

0-2*(-46.1) = 92.2 kJ

(3*130.6+191.5) - (2*192.3) = 198.7 J -> .1987kJ

Gibbs Free Energy Equation:
92.2kJ - .1987kJ = 92.0kJ

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