[Malekythhexane]

Find the isomer alkenes A,B,C,D,E with the molecular formula C6H12, knowing their behavior with K2Cr2O7 and H2SO4(Oxidation), and write the equations.
A)The A isomer forms threw oxidation 1 cetone.
A = 2 ethyl 1 butene
B) B and C isomers form threw oxidation 1 single acid.
B = 1 hexene
C = 2 hexene
C)The isomer D form threw oxidation:1 acetone, and 1 acid.
D = 2 emthyl 2 pentene
D)The isomer E form threw oxidation: CO2, H20 and the acid 2,2 dimethylpropane
E = 3,3 dimethyl 1 butene.

I think i made it good

[Dan]

"Threw" is the past participle of the verb "to throw" - the word you are looking for is "through", which is pronounced the same way.

Anyway, to business...

A)The A isomer forms threw oxidation 1 cetone.
A = 2 ethyl 1 butene

By "cetone", do you mean "acetone"?

2-ethyl-1-butene yould give pentan-3-one and CO₂ as products - no acetone would be produced at all.

B) B and C isomers form threw oxidation 1 single acid.
B = 1 hexene
C = 2 hexene

1-hexene would give pentanoic acid and CO₂.
2-hexene would give butanoic acid and ethanoic acid as products.

Try to think of an alkene that gives only one product.

C)The isomer D form threw oxidation:1 acetone, and 1 acid.
D = 2 emthyl 2 pentene

Correct

D)The isomer E form threw oxidation: CO2, H20 and the acid 2,2 dimethylpropane
E = 3,3 dimethyl 1 butene.

By "the acid 2,2 dimethylpropane", I assume you mean "2,2-dimethylpropanoic acid". Your answer is correct.

[Malekythhexane]

can you please tell me what are the A,B,C?i can't find them. can B,C be geometric isomers?

[Dan]

No, you have to try yourself, it is against Forum Policy to simply give you the answer.

You have got D and E correct. How did you decide on those answers? What was you logic? Apply that logic to A, B and C.

[Malekythhexane]

No, you have to try yourself, it is against Forum Policy[/url] to simply give you the answer.

You have got D and E correct. How did you decide on those answers? What was you logic? Apply that logic to A, B and C.

i did apply that login to A,B,C too but it didnt worked...

might C be 2,3-dimethyl-2-butene and B 2,3-dimethyl-1-butene ?

[Malekythhexane]

im sure 2 ethyl 1 butene gives acetone , double blond at O maybe?
ok you have to answer, tryied every isomer...

[Malekythhexane]

a must give ketone not acetone ;0
and i think A is right, since il get 2-methyl-3-pentanone and its ketone.

chec here https://www.cdli.ca/courses/chem2202/unit03_org03_ilo03/b_activity.html 2 methyl 3 pentanone is ketone, A is right.

[Dan]

Ok, I think I can see what the problem is.

Oxidation of isomer A produces a single ketone as the only product

The only possibility is 2,3-dimethylbut-2-ene, which will produce only one product: propanone (also called acetone).

Similarly, oxidation of B or C produce a single acid as the only product.