[BreakingBad20]

A cell-free enzyme is used in a batch reaction process for the manufacture of sunscreen
lotion. Vmax for the enzyme is 10mM.hr-1, Km is 6.8 mM, and the initial substrate concentration is
14mM. Determine the final substrate concentration, given a batch reaction time of 3 hours.

t(b) = (Km/Vmax)ln(So/Sf) + (So - Sf)/Vmax
3 = (6.8/10)ln(14/Sf) + (14 - Sf)/10
Sf + 6.8ln(Sf) = 1.95
This is my problem in the line up above, how do I eliminate this "ln" or is there another equation I can use?

[kishna009]

you either trial values of Sf so that LHS and RHS are equal or else apply logarithm series or else differetiate with respect to Sf and then follow runge kutta method to get values for time of 3 hrs,.. if u r not clear of this,,,reply... i will tell u the steps