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Topic: Making Organic Compound help  (Read 3130 times)

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Offline sinjid9

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Making Organic Compound help
« on: December 19, 2011, 04:46:46 PM »
How do you make 2-Propoxy-3-Cholorobutane. Or more specifically how do you make the parent chain in that reaction (the alcohol) from an alkene?

Offline Vidya

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Re: Making Organic Compound help
« Reply #1 on: December 19, 2011, 07:09:56 PM »
you can try an addition reaction on 2-Butene.now you need to select the reagent which can give lead to addition of  propoxy and Cl on the double bond

Offline sinjid9

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Re: Making Organic Compound help
« Reply #2 on: December 19, 2011, 08:47:35 PM »
So I used 2-Butene and went to hydrohalogenation with HCI but I lose the double bond, unless you don't need it for hydration. Also, Can I start from 2-Butyne? and undergo hydrohalogenation adding the Cl and H where I want?
« Last Edit: December 19, 2011, 09:06:24 PM by sinjid9 »

Offline Vidya

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Re: Making Organic Compound help
« Reply #3 on: December 19, 2011, 10:33:22 PM »
Do not do hydrohalogenation.It will not give you desired product.Use Cl2  and CH3CH2CH2OH First Cl2 is added by electrophilic addition and after that CH3CH2CH2OH

Offline CrimpJiggler

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Re: Making Organic Compound help
« Reply #4 on: December 22, 2011, 07:09:34 PM »
From 2-butene you could convert the alkene into an epoxide with a peracid then convert the epoxy into a halohydrin and finally, convert the hydroxyl group of the halohydrin into an ether. I don't really understand the question, where you specifically given 2-butene as the starting reagent? If so, the epoxy route is perfect.

Offline orgopete

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Re: Making Organic Compound help
« Reply #5 on: December 23, 2011, 11:27:17 AM »
From 2-butene you could convert the alkene into an epoxide with a peracid then convert the epoxy into a halohydrin and finally, convert the hydroxyl group of the halohydrin into an ether. I don't really understand the question, where you specifically given 2-butene as the starting reagent? If so, the epoxy route is perfect.

Au contraire, the problem is how do you alkylate the chlorohydrin? Won't the alkoxide of a chlorohydrin form an epoxide again? I suggest following Uma's route.
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