[Math99]

Hello,

I have a problem with this task:

"Water with pH 5 and reduction potential +0.30 V flows through copper pipe at 25 °C. Calculate how much copper dissolves (in ppm) in water due to corrosion of this pipe. Standard reduction potential of copper Cu0/Cu2+ is 0.34 V."

I spent lot of hours with lot of calculations without any glory Please, is there anybody who could try to help me?

This figure could be helpful:

http://www.advancedaquarist.com/2003/5/chemistry_album/figure3.gif

I tried to use Nernst equation:

Eh = E0 - (RT / nF)*(lnQ).

The main equation I used was:

Cu + 2H+ -> Cu2+ + H2.

Without any glory

[Vidya]

Now lnQ =ln [CU2+]/[H+]^2
now you know that pH =5
[H+]= 10^-pH=10^-5
Ecell =0.30V
E0 cell= 0.34V
Plug in the values in the Nernst equation and you will get [CU2+]

[Math99]

I do not think so  ...