Topic: Does adding solid to a reaction at equilibrium shift equilibrium? (Read 5393 times)

TheAbsoluTurk · « **on:** January 01, 2012, 02:45:15 AM »

The problem in question:

4Cu0_s + energy

2Cu₂O_s + O₂

The equilibrium will shift to the right as a result of:

   a. adding CuO_s

   b. removing O₂

   c. adding a catalyst

   d. decreasing temperature

I know it is either a. or b.

Thanks for any help you can provide.

UG · « **Reply #1 on:** January 01, 2012, 03:02:08 AM »

Adding more of the solid doesn't affect the equilibrium

TheAbsoluTurk · « **Reply #2 on:** January 01, 2012, 03:11:03 AM »

Thank you.

Borek · « **Reply #3 on:** January 01, 2012, 06:18:58 AM »

Also note: it is not CuO_s, it is CuO(s).

vladi307 · « **Reply #4 on:** January 01, 2012, 02:31:48 PM »

The concentration of a solid substance practically didn't change during the reaction. It is equal to the ratio d/Mr, d = density of the solid (g/ml) and Mr = molecular weight (g/mol). For this reason, adding of CuO(s) didn't affect the equilibrium of the mentioned reaction.

Topic: Does adding solid to a reaction at equilibrium shift equilibrium? (Read 5393 times)

TheAbsoluTurk

Does adding solid to a reaction at equilibrium shift equilibrium?

UG

Re: Does adding solid to a reaction at equilibrium shift equilibrium?

TheAbsoluTurk

Re: Does adding solid to a reaction at equilibrium shift equilibrium?

Borek

Re: Does adding solid to a reaction at equilibrium shift equilibrium?

vladi307

Re: Does adding solid to a reaction at equilibrium shift equilibrium?

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