NaHCO3 + HCl NaCl + H2O + CO2 12.7KJ
This reaction you have written is good, but you need to add your change in enthalpy sign in front of the number (for example, ΔH
reaction = 12.7 kJ/mol ). You are told that the reaction absorbs 12.7 kJ of heat, this means that for every mole of the reaction you have written above the energy absorbed is 12.7 kJ. Part B asks how much heat is absorbed if 0.5 moles of CO
2 gas is produced, ie, the entire reaction is halved, this part should be simple enough? For part C you need to find firstly how many moles of HCl is 3.01 x 10
23 molecules of HCl, do you know how to do this with Avagadro's number?