November 27, 2024, 02:45:06 AM
Forum Rules: Read This Before Posting


Topic: Help with thermochemical reaction  (Read 6352 times)

0 Members and 4 Guests are viewing this topic.

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Help with thermochemical reaction
« on: January 25, 2012, 07:47:58 PM »
I have a three part question:

Aqueous sodium hydrogen carbonate solution reacts with hydrogen chloride. The reaction produces salt, water and carbon dioxide gas. The reaction absorbs 12.7KJ of heat. Answer the following questions:

A. Write the balanced thermochemical equation representing this reaction.

B. How much energy will be absorbed if 1/2 moles of carbon dioxide gas were produced in this reaction. Write the balanced thermochemical equation for this reaction.

C. How much energy will be absorbed if 3.01 x 1023 molecules of aqueous HCl were present in the system. Write the balanced thermochemical equation for this reaction.

Offline Arkcon

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7367
  • Mole Snacks: +533/-147
Re: Help with thermochemical reaction
« Reply #1 on: January 25, 2012, 08:46:52 PM »
Well, lets try to start this.  Begin by drawing a balanced chemical reaction.  That's not only what part a asks for, you'll also need it to figure out the rest.  You've been given products and reactants, and you've been told the reaction absorbs heat, so where would that go?
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #2 on: January 25, 2012, 10:16:47 PM »
Here's what I have to start with:

NaHCO3 + HCl  :rarrow: NaCl + H2O + CO2 12.7KJ

Offline UG

  • Full Member
  • ****
  • Posts: 822
  • Mole Snacks: +134/-15
  • Gender: Male
Re: Help with thermochemical reaction
« Reply #3 on: January 26, 2012, 01:16:35 AM »
NaHCO3 + HCl  :rarrow: NaCl + H2O + CO2 12.7KJ
This reaction you have written is good, but you need to add your change in enthalpy sign in front of the number (for example, ΔHreaction = 12.7 kJ/mol ). You are told that the reaction absorbs 12.7 kJ of heat, this means that for every mole of the reaction you have written above the energy absorbed is 12.7 kJ. Part B asks how much heat is absorbed if 0.5 moles of CO2 gas is produced, ie, the entire reaction is halved, this part should be simple enough? For part C you need to find firstly how many moles of HCl is 3.01 x 1023 molecules of HCl, do you know how to do this with Avagadro's number?

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #4 on: January 26, 2012, 02:16:26 AM »
I think I do. The problem I am finding is the changes to the equation gives me the same answer and it doesn't seem right that both answers would be the same. 1/2 CO2 and 3.01 x 1023 means I half the entire equation in both instances, correct?

Offline UG

  • Full Member
  • ****
  • Posts: 822
  • Mole Snacks: +134/-15
  • Gender: Male
Re: Help with thermochemical reaction
« Reply #5 on: January 26, 2012, 02:24:15 AM »
1/2 CO2 and 3.01 x 1023 means I half the entire equation in both instances, correct?
Yes I agree, the answer will be the same on both instances.

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #6 on: January 26, 2012, 02:43:26 AM »
Here's what I came up with for both:

1/2NaHCO3 + 1/2HCl  :rarrow: 1/2NaCl + 1/2H2O + 1/2CO2 ΔH=6.35KJ

Correct?

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #7 on: January 26, 2012, 02:44:20 AM »
Do any of you guys know what my professor is talking about when he asks me to define "isolated reaction"?

Offline UG

  • Full Member
  • ****
  • Posts: 822
  • Mole Snacks: +134/-15
  • Gender: Male
Re: Help with thermochemical reaction
« Reply #8 on: January 26, 2012, 03:01:37 AM »
1/2NaHCO3 + 1/2HCl  :rarrow: 1/2NaCl + 1/2H2O + 1/2CO2 ΔH=6.35KJ

Correct?
Yes, very much so.

Do any of you guys know what my professor is talking about when he asks me to define "isolated reaction"?
Apart from maybe "a reaction which occurs in an isolated system" I have no idea what he means.  :-\

http://en.wikipedia.org/wiki/Isolated_system

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #9 on: January 26, 2012, 03:11:20 AM »
Could he be talking about an isolation reaction? Not that I know what that is, but it sounds more familiar ...

Offline UG

  • Full Member
  • ****
  • Posts: 822
  • Mole Snacks: +134/-15
  • Gender: Male
Re: Help with thermochemical reaction
« Reply #10 on: January 26, 2012, 03:21:22 AM »
I can't really say without knowing what context these terms were used in.

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #11 on: January 26, 2012, 03:25:24 AM »
Unfortunately it is from a list of definitions he expects us to know. The list is as follows:

Photon
Principle Quantum Number
Enthalpy
Heat of reaction
Isolated reaction

I have all the others, but this one cannot be found anywhere.
 ???

Offline UG

  • Full Member
  • ****
  • Posts: 822
  • Mole Snacks: +134/-15
  • Gender: Male
Re: Help with thermochemical reaction
« Reply #12 on: January 26, 2012, 03:30:21 AM »
Ah ok, if you're talking about enthalpy and heat of reaction then isolated reaction could very well mean what I said before "a reaction which occurs in an isolated system, there is no exchange of energy and mass". I am 90% sure this is what he wants ;D

Offline shilohmedia

  • Regular Member
  • ***
  • Posts: 9
  • Mole Snacks: +0/-0
Re: Help with thermochemical reaction
« Reply #13 on: January 26, 2012, 03:34:30 AM »
Dude, thank you so much. This has been eating at me because I cannot find it in the book in those terms anywhere or on the internet. I have been haunted by thinking he surely has a typo here. The problem is my test is this weekend (a weekend only class). That makes sense when you describe it.

Sponsored Links