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Topic: Solubility and Precipitation  (Read 2622 times)

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Offline Boxxxed

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Solubility and Precipitation
« on: February 05, 2012, 04:58:45 PM »
When ksp=10-10=[Ba2+][SO42-]

When Ba=[10-3]
         SO4=[10-2.3]
Q=10-5.3 >>> 10-10.0

So to find out how much precipitates wouldn't this be correct?

[10-3-x][10-2.3-x]=10-10

Instead the pdf uses this method.

(x) (10-2.3) = 10-10.0
x = 10-7.7
BaSO4 precipitation = 10-3 -10-7.7 ~ 10-3 molL-1

It is saying that SO4 is constant because equilibrium is controlled by dissolution of a mineral with much higher ksp than barite. But shouldn't the first method work anyway?

Offline Borek

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Re: Solubility and Precipitation
« Reply #1 on: February 05, 2012, 05:47:14 PM »
It is saying that SO4 is constant because equilibrium is controlled by dissolution of a mineral with much higher ksp than barite. But shouldn't the first method work anyway?

How can the method work if it assumes concentration of SO42- changes, while you are told it is constant?
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Offline Boxxxed

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Re: Solubility and Precipitation
« Reply #2 on: February 05, 2012, 07:51:58 PM »
Because it has to change when barite precipitates? Its concentration must decrease equal to the amount of Ba that decreases. Ba doesn't just precipitate by itself, BaSO4 does.

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Re: Solubility and Precipitation
« Reply #3 on: February 06, 2012, 04:04:50 AM »
It doesn't have to change - there is a SOURCE of SO42- that keeps its concentration constant.
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