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Topic: Redox reaction  (Read 2330 times)

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Offline Rutherford

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Redox reaction
« on: March 06, 2012, 10:32:37 AM »
I don't know how to balance this reaction:
GeS2*4Ag2S+K2CO3+KNO3-->K2GeO3+K2SO4+KNO2+Ag+CO2
S, Ag and C are changing their oxidation states, so how to write the oxidation and reduction half-reactions?

Offline AWK

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Re: Redox reaction
« Reply #1 on: March 06, 2012, 11:19:30 AM »
Calculate net number of removed electrons for the whole molecule
GeS2*4Ag2S = Ag8GeS6

AWK

Offline Rutherford

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Re: Redox reaction
« Reply #2 on: March 06, 2012, 11:32:28 AM »
3S-2 are converted to 3 S+6
8Ag+ are converted to 8Ag0
3*(-2)+8*1=2
3*6+8*0=18
18-2=16e-
16e- are deducted?

Offline Rutherford

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Re: Redox reaction
« Reply #3 on: March 07, 2012, 08:15:18 AM »
Oh, I made a mistake. There are 6S atoms so the electron change is -40e- and for the nitrate and nitrite is +2e- and when I multyply this by 20 the equation can be easily solved. Thanks very much!

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