CH3 CH3
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I-C-H + NaCN CN-C-H + I-
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HO-C-H OH-C-H
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CH3 CH3
i have sneaky suspicion that after the CN takes the place of I it switches around to the back of the carbon chain but thats as far as i can get.
You get backside attack in Sn2 displacements, in your case you don't define the stereochemistry. But the CN will end up on the opposite side to the I.