[majuji]

Hi guys, would greatly appreciate it if you could help me with these calculations please
lab session: determination of the decossiation constant of acetic acid by conductivity.
questions: 1; calculate the cell constant 2; correct all your readings for the cell constant and the conductivity of water  3; determine Λm° using graphycal method, 4; for each solution determine a and hence k.

this is the data from lab:

Solution          :  Conductivity µS cm-1
Standrad KCl      :        2.69  
Mili-q water        :        6.90  
0.1M acetic acid    :      491
0.05M acetic acid   :      343
0.025M acetic acid  :      246
0.010M acetic acid  :      152.8  
0.005M acetic acid  :      106.6  
0.0025M acetic acid :      75.8  
0.0010M acetic acid :      48.5  
morality of the standard KCl= 2.777 mS cm-1
i belive Cell constant = Molarity of standard KCl / Measured average conductivity of KCl (mS).. does that sound right ?
i literally have no idea how to go on about most of it tho i have some undrstanding please help if you can.
thank you very much in advance. really great-full for any help you can put in.