Determine the number of entities (atoms or molecules) of N2 in a closed 6.07 L container at a pressure of 6.41×103 torr and a temperature of -126.83 °C. Report your answer to three significant figures.
n=RT/PV
6410torr/760torr = 8.434211 atm
-126.83 degC + 273.15 = 146.32 K
n = (0.08206Latm/molK)(146.32K)/(8.434211atm)(6.07K)
n=0.234532 molN2 x (6.02x10^23)
= 1.41x10^23 molecules.
What have I done wrong?