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Topic: formula of compound and moles  (Read 2834 times)

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Offline richplow

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formula of compound and moles
« on: April 19, 2012, 02:05:34 AM »
the problem states:
a compound of chlorine and fluorine, ClFn, reacts at about 75 degrees C with uranium metal to produce uranium hexafluoride, UF6, and chlorine monofluoride, CIF(g). a quantity of uranium produced 3.53 g UF6 and 343 mL ClF at 75 degrees C and 2.50 atm. what is the formula (n) of the compound?

i got the moles of ClF(g) = 0.30 mol
and the moles of UF6 = 0.01mol

but how do i get the formula of ClFn after that? i know I'm supposed to get the mol of F from the two products, but how?? i really want to understand this

the answers supposed to be ClF3.

Offline UG

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Re: formula of compound and moles
« Reply #1 on: April 19, 2012, 02:16:15 AM »
i know I'm supposed to get the mol of F from the two products, but how??
Well if you had 1 molecule of ClF, how many F atoms are there? And if you had 1 molecule of UF6 how many F atoms are there?

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