Yesterday I was a liitle bit to lazy to post results of my "investigation" into the problem. I am finishing work on the equation balancing program (some of you have already seen screenshots) and I am testing it whenever possible. Thus I have checked how this reaction can be balanced.
Lets start with Cotex approach:
2 NH
4ClO
4 + 8 Mg -> 8 MgO + N
2 + 4 H
2 + Cl
2it is hot and there are hydrogen and free chlorine, so the first obvious change is
2 NH
4ClO
4 + 8 Mg -> 8 MgO + N
2 + 3 H
2 + 2HCl
MgO and HCl? Doesn't look like stable combination:
2 NH
4ClO
4 + 5 Mg -> 5 MgCl
2 + N
2 + 8HCl
However, there are also other possibilities, like:
2 NH
4ClO
4 + 4 Mg -> 4 MgO + N
2 + 4 H
2O + Cl
2or
2 NH
4ClO
4 + 5 Mg -> 4 MgO + MgCl
2 + N
2 + 4 H
2O
I would say the last one seems the best to me, as there are no highly reactive substances between the products.
Probably in reality products of this reaction can be a mixture of all substances mentioned plus a few others, as a lot will depend on the reaction pathways and the circumstances - in open gases may be removed before they can react with other reagents, also in open oxygen from air may play some role. Some chlorine oxides, or traces of ammonia between products will also not rise a brow. At least my brow