well....i'm coming out with a different answer but close so:
1 year=365 days=...=3153600 seconds
the t
1/2=2.4*10
4years convert that to seconds t
1/2=7.56864*10
11seconds
since you dont have the actual equation of the decay let assume that 1mol of Pu gives you 1mol of He and 1mol of the other substance X
at the half-life you will have 0.5mol of Pu, 0.5 mol of He and 0.5mol of X, similarly 0,0001mol of Pu will give you 0.0001 mol He. multiply that with the avogadro number. you will end up with 6.02214*10
19 helium atoms at half-life (at 7.56864*10
11 seconds). to get the He atoms per second divide it by the half life in seconds and i get almost 8*10
7although not quite sure since you give a different answer