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Topic: Calculating grams of solute using vapor pressure, temp, and grams of solvent  (Read 4728 times)

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vmdenslow

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Would I do this type of equation by using Raoult's Law? The actual problem says "How many grams of sucrose C12H22O11 must be added to 55 g of water to give a solution with a vapor pressure 2.0 mmHg less than that of pure water at 20 degrees Celcius (the vapor pressure of water at 20 degrees Celcius is 17.5 mmHg).

I know that you need to convert the grams to moles, but I don't remember how to change the grams of sucrose to moles without knowing either how many grams or moles there were to begin with.

Offline Donaldson Tan

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using raoult's law means assume ideal solution.

Using 1atm, 20C as the reference state,

µi = µ* + RT.ln(Xi)

µi = µ* + RT.ln(Pi/P*)

comparing the 2 equivalent equations, you end up with

Xi = Pi/P*

let molar mass of sucrose be M
let mass of sucrose used be m
=> Xi = 55/(55 + m/M)

Quote
..to give a solution with a vapor pressure 2.0 mmHg less than that..
=> Pi/P* = (17.5 - 2)/17.5

from here, you should've no problem arriving at the answer
« Last Edit: November 20, 2005, 04:30:06 PM by geodome »
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