Oh boy, this is getting more complicated...
So you started with five known compounds in your reaction mixture - your acid chloride, curcumin, desmethoxy curcumin, bis-desmethoxycurcumin, and pyridine. The ratio of your mixture of curcumins to acid chloride was 1:1.2. If the reaction works at all, you shouldn't expect to see a huge difference in reactivity between any of your phenols (you have now described six different phenols from your three starting materials) and you still have three enols which might also be expected to react. The phenols are far enough away from each other that reacting with one shouldn't change the reactivity of the other. So assuming the acid chloride only reacted with the phenols, you can expect at least four different monoalkylated products and three different dialkylated products. The fact that you only saw two different spots and that the three starting materials are all still present leads me to suspect that the reaction didn't work at all.
If the intensities of your three starting material spots are very different - for instance, if you have say 90% curcumin and only 5% each of the other two - then there is a slight chance that the two new spots are mono- and di-substituted curcumin, and that the products from reactions with the other two starting materials were just too dilute to show. In that case, either spotting them in a more concentrated solution or possibly visualizing your plate (an iodine chamber would probably work well for this) may bring out the additional spots.
If you have easy access to an MS, you might want to throw this mixture on, just to see if you get anything related to product. If you do, it might be worth tracking down; if you don't, I'd worry more about how to set up the next reaction than how to clean this one up.