December 26, 2024, 06:55:23 AM
Forum Rules: Read This Before Posting


Topic: Equilibrium Concentration  (Read 1826 times)

0 Members and 1 Guest are viewing this topic.

Offline zeroblade

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Equilibrium Concentration
« on: June 06, 2012, 12:37:09 PM »
I have a question about an equilibrium example in my textbook that I believe is giving the incorrect answer.

Q: The Haber Process is the industrial method for the production of ammonia: 3H2(g) + N2(g) :lequil: 2NH3(g). If the pressure in a vessel containing hydrogen gas and nitrogen gas is increased, how is the Haber process affected?

A) It is favored
B) It is disfavored
C) It is unaffected
D) It is impossible to tell from the given information

My book says that A) is the answer since an increase in pressure will cause the system to shift to the right where there are fewer moles of gas to compensate for the pressure.

However, in my opinion it should be D) since without extra information you can't tell if the pressure increase is from increase in volume or through the addition of inert gas to the system.

Can anyone shed some light on this?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Equilibrium Concentration
« Reply #1 on: June 06, 2012, 01:36:16 PM »
Interesting point. Usually if the pressure is increased by the addition of the inert gas it is stated verbatim in the question, but you are right that there is some ambiguity here.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links