[marifergarz]

Hi everyone! I need help solving this problem. Thanks a lot in advance!


GIVEN THE FOLLOWING BALANCED  EQUATION:    
C3H8 + 5 O2  →  3 CO2 + 4 H2O

75 GRAMS OF HYDROCARBON FUEL IS COMBINED WITH 300 GRAMS OF OXYGEN:

A)DETERMINE THE GRAMS OF EXCESS REAGENT USED.



B)  DETERMINE HOW MANY GRAMS OF WATER is formed.

[sjb]

Hi everyone! I need help solving this problem. Thanks a lot in advance!


GIVEN THE FOLLOWING BALANCED  EQUATION:    
C₃H₈ + 5 O₂    3 CO₂ + 4 H₂O

75 GRAMS OF HYDROCARBON FUEL IS COMBINED WITH 300 GRAMS OF OXYGEN:

A)DETERMINE THE GRAMS OF EXCESS REAGENT USED.



B)  DETERMINE HOW MANY GRAMS OF WATER is formed.

How many moles of hydrocarbon are there? How many moles of oxygen?

[marifergarz]

Hi everyone! I need help solving this problem. Thanks a lot in advance!


GIVEN THE FOLLOWING BALANCED  EQUATION:    
C₃H₈ + 5 O₂    3 CO₂ + 4 H₂O

75 GRAMS OF HYDROCARBON FUEL IS COMBINED WITH 300 GRAMS OF OXYGEN:

A)DETERMINE THE GRAMS OF EXCESS REAGENT USED.



B)  DETERMINE HOW MANY GRAMS OF WATER is formed.

How many moles of hydrocarbon are there? How many moles of oxygen?

It is not given  

[Borek]

How many moles of hydrocarbon are there? How many moles of oxygen?

It is not given   

Yes it is. You are given formula so you can calculate molar mass, you are given mass so you can calculate number of moles.

[marifergarz]

How many moles of hydrocarbon are there? How many moles of oxygen?

It is not given   

Yes it is. You are given formula so you can calculate molar mass, you are given mass so you can calculate number of moles.

That's everything my instructor gave me. She said we were supposed to figure out with everything that's given.

[Borek]

And I told you precisely what to do.

Start calculating molar masses of C₃H₈ and O₂.

[marifergarz]

And I told you precisely what to do.

Start calculating molar masses of C₃H₈ and O₂.

So it would be 12*3 + 1*8  = 44  and 16*2 = 32  ?

[sjb]

And I told you precisely what to do.

Start calculating molar masses of C₃H₈ and O₂.

So it would be 12*3 + 1*8  = 44  and 16*2 = 32  ?

Don't forget your units, but yes. How many moles of hydrocarbon do you therefore have, and of oxygen?

[marifergarz]

And I told you precisely what to do.

Start calculating molar masses of C₃H₈ and O₂.

So it would be 12*3 + 1*8  = 44  and 16*2 = 32  ?

Don't forget your units, but yes. How many moles of hydrocarbon do you therefore have, and of oxygen?

Sorry for the units! And so you would use the formula moles = mass / molar mass. mass of hydrocarbon = 1.01 * 8 / 44 = 0.18. Would I do the same for the oxygen  So 16*2/32 = 2 I'm a bit confused with moles since we did that a while ago

[sjb]

Sorry for the units! And so you would use the formula moles = mass / molar mass. mass of hydrocarbon = 1.01 * 8 / 44 = 0.18. Would I do the same for the oxygen  So 16*2/32 = 2 I'm a bit confused with moles since we did that a while ago

Not hydrogen, but hydrocarbon.

75 g, at 44 g/mol is how many moles?