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Topic: Gas Combustion Problem  (Read 5641 times)

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Offline marifergarz

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Gas Combustion Problem
« on: June 17, 2012, 10:57:11 AM »
Hi everyone! I need help solving this problem. Thanks a lot in advance!


GIVEN THE FOLLOWING BALANCED  EQUATION:    
C3H8 + 5 O2  →  3 CO2 + 4 H2O

75 GRAMS OF HYDROCARBON FUEL IS COMBINED WITH 300 GRAMS OF OXYGEN:

A)DETERMINE THE GRAMS OF EXCESS REAGENT USED.



B)  DETERMINE HOW MANY GRAMS OF WATER is formed.

Offline sjb

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Re: Gas Combustion Problem
« Reply #1 on: June 17, 2012, 11:29:03 AM »
Hi everyone! I need help solving this problem. Thanks a lot in advance!


GIVEN THE FOLLOWING BALANCED  EQUATION:    
C3H8 + 5 O2   :rarrow:  3 CO2 + 4 H2O

75 GRAMS OF HYDROCARBON FUEL IS COMBINED WITH 300 GRAMS OF OXYGEN:

A)DETERMINE THE GRAMS OF EXCESS REAGENT USED.



B)  DETERMINE HOW MANY GRAMS OF WATER is formed.


How many moles of hydrocarbon are there? How many moles of oxygen?

Offline marifergarz

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Re: Gas Combustion Problem
« Reply #2 on: June 17, 2012, 04:10:22 PM »
Hi everyone! I need help solving this problem. Thanks a lot in advance!


GIVEN THE FOLLOWING BALANCED  EQUATION:    
C3H8 + 5 O2   :rarrow:  3 CO2 + 4 H2O

75 GRAMS OF HYDROCARBON FUEL IS COMBINED WITH 300 GRAMS OF OXYGEN:

A)DETERMINE THE GRAMS OF EXCESS REAGENT USED.



B)  DETERMINE HOW MANY GRAMS OF WATER is formed.


How many moles of hydrocarbon are there? How many moles of oxygen?

It is not given   :-\

Offline Borek

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Re: Gas Combustion Problem
« Reply #3 on: June 17, 2012, 04:37:04 PM »
How many moles of hydrocarbon are there? How many moles of oxygen?

It is not given   :-\

Yes it is. You are given formula so you can calculate molar mass, you are given mass so you can calculate number of moles.
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Offline marifergarz

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Re: Gas Combustion Problem
« Reply #4 on: June 17, 2012, 05:49:41 PM »
How many moles of hydrocarbon are there? How many moles of oxygen?

It is not given   :-\

Yes it is. You are given formula so you can calculate molar mass, you are given mass so you can calculate number of moles.

That's everything my instructor gave me. She said we were supposed to figure out with everything that's given.

Offline Borek

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Re: Gas Combustion Problem
« Reply #5 on: June 17, 2012, 05:57:20 PM »
And I told you precisely what to do.

Start calculating molar masses of C3H8 and O2.
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Offline marifergarz

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Re: Gas Combustion Problem
« Reply #6 on: June 17, 2012, 07:39:19 PM »
And I told you precisely what to do.

Start calculating molar masses of C3H8 and O2.

So it would be 12*3 + 1*8  = 44  and 16*2 = 32  ?

Offline sjb

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Re: Gas Combustion Problem
« Reply #7 on: June 17, 2012, 08:15:09 PM »
And I told you precisely what to do.

Start calculating molar masses of C3H8 and O2.

So it would be 12*3 + 1*8  = 44  and 16*2 = 32  ?


Don't forget your units, but yes. How many moles of hydrocarbon do you therefore have, and of oxygen?

Offline marifergarz

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Re: Gas Combustion Problem
« Reply #8 on: June 17, 2012, 09:08:45 PM »
And I told you precisely what to do.

Start calculating molar masses of C3H8 and O2.

So it would be 12*3 + 1*8  = 44  and 16*2 = 32  ?


Don't forget your units, but yes. How many moles of hydrocarbon do you therefore have, and of oxygen?

Sorry for the units! And so you would use the formula moles = mass / molar mass. mass of hydrocarbon = 1.01 * 8 / 44 = 0.18. Would I do the same for the oxygen  ??? So 16*2/32 = 2 I'm a bit confused with moles since we did that a while ago

Offline sjb

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Re: Gas Combustion Problem
« Reply #9 on: June 18, 2012, 02:06:33 AM »
Sorry for the units! And so you would use the formula moles = mass / molar mass. mass of hydrocarbon = 1.01 * 8 / 44 = 0.18. Would I do the same for the oxygen  ??? So 16*2/32 = 2 I'm a bit confused with moles since we did that a while ago

Not hydrogen, but hydrocarbon.

75 g, at 44 g/mol is how many moles?

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