January 15, 2025, 10:01:19 PM
Forum Rules: Read This Before Posting


Topic: Electrochemistry (theory)  (Read 3410 times)

0 Members and 2 Guests are viewing this topic.

Offline Rutherford

  • Sr. Member
  • *****
  • Posts: 1868
  • Mole Snacks: +60/-29
  • Gender: Male
Electrochemistry (theory)
« on: June 18, 2012, 01:57:32 PM »
I have some difficulties to understand few thing here.
1.Nernst equation:E=Eo+2.3RT/Fz*log[Ox]/[Red.]
a)Is the other simbol for E varphi?
b)What is [Ox] and what is [Red.], I found that they are the concentrations of the substances that take part in oxidation or reduction process, so why in the reaction:
Zn2++2e- ::equil:: Zn, is [Ox]=[Zn2+] when Zn2+ gets reduced, so it takes part in the process of reduction?

2.If I use Pt electrodes for a el. cell (for example, Zn and Ag solutions):
a)If Ag+ gets reduced where from does it get the electron when Pt is inert
b)How does Zn drop 2 electrons if all Zn is presented as Zn2+?
Do these have some connection with the bridge?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27895
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Electrochemistry (theory)
« Reply #1 on: June 18, 2012, 02:33:18 PM »
Is the other simbol for E varphi?

Huh?

Quote
What is [Ox]


Concentration of the oxidized specie.

Quote
If Ag+ gets reduced where from does it get the electron when Pt is inert

Pt is a just a conductor. You can't have just Ag+ reduced, it requires other half cell where something gets oxidized. It doesn't have to be in the same solution, but you have to allow charge transfer to close the circuit.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Rutherford

  • Sr. Member
  • *****
  • Posts: 1868
  • Mole Snacks: +60/-29
  • Gender: Male
Re: Electrochemistry (theory)
« Reply #2 on: June 19, 2012, 10:20:25 AM »
Quote
Concentration of the oxidized specie.

That explains why H+ is [Ox], too. I suppose that H2 is [Red.] then, and Zn not because it is solid.

I meant 2 different solution (a cell, Ag and Zn with the salt bridge), Zn gets oxidized and Ag gets reduced, but I don't understand how Zn gets oxidized if all Zn in the solution is present as Zn2+ it can't lose any more electrons. Where from does Ag+ get electrons so it gets reduced?

Offline Olympiad_Tutor

  • Regular Member
  • ***
  • Posts: 42
  • Mole Snacks: +1/-2
  • BS in Chemistry, PhD in Biochemistry
Re: Electrochemistry (theory)
« Reply #3 on: June 22, 2012, 10:27:31 PM »
Zn   -2e -> Zn2+
Ag+   +e -> Ag
National Olympiad winner will tutor AP Chem and Chemistry Olympiad students. Tutoring is done online via a whiteboard with Voice, Drawing capabilities. PM for details.

Offline Rutherford

  • Sr. Member
  • *****
  • Posts: 1868
  • Mole Snacks: +60/-29
  • Gender: Male
Re: Electrochemistry (theory)
« Reply #4 on: June 23, 2012, 02:49:55 AM »
I don't understand where Zn comes from. There are only Zn2+ ions in the solution.
Where does the ecletron in the Ag+ solution come from?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27895
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Electrochemistry (theory)
« Reply #5 on: June 23, 2012, 04:28:44 AM »
If there is no metallic Zn there will be no reaction taking place. As you correctly spotted, for redox reaction you need both reducing and oxidizing agent at the same time, otherwise there is either no source of electrons or no electron sink.
« Last Edit: June 23, 2012, 04:58:58 AM by Borek »
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Rutherford

  • Sr. Member
  • *****
  • Posts: 1868
  • Mole Snacks: +60/-29
  • Gender: Male
Re: Electrochemistry (theory)
« Reply #6 on: June 23, 2012, 05:08:18 AM »
So, on the anode and the cathode there should be a thin layer of Zn and Ag respectively so there will be made an equilibrium (in both half-cells) with the ions in the solution?

Sponsored Links