How many co-ordinate bonds are present in the nitrate anion?
By drawing the structure I would say 2, but I don't understand how they have formed. Nitrogen should have 6 electrons so that 2 electrons would make with an O atom a double cov. bond, and the other 2 electron pairs would be donated to the other 2 O atoms. Does this mean that nitrogen that makes NO3- should be negative charged, so after the donating of the 2 pairs it gets positive and the 2 oxygen negative (the compound is then negative as it is)?