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Topic: C13 NMR  (Read 7238 times)

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Offline rleung

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C13 NMR
« on: December 02, 2005, 10:47:28 AM »
Hi,

I am confused as to why this molecule only gives 3 signals in a 13C NMR.  Is it because the signal for the C that has a double bond to O is so small that it become insignificant?  Even if it becomes insignificant, technically, it produces a signal, right?  Thanks.

Ryan

Offline Borek

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Re:C13 NMR
« Reply #1 on: December 02, 2005, 12:18:57 PM »
Which molecule?
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Offline sdekivit

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Re:C13 NMR
« Reply #2 on: December 02, 2005, 02:54:45 PM »
Hi,

I am confused as to why this molecule only gives 3 signals in a 13C NMR.  Is it because the signal for the C that has a double bond to O is so small that it become insignificant?  Even if it becomes insignificant, technically, it produces a signal, right?  Thanks.

Ryan

if it's a ketone the C-peak of this group will be less intens (1/3 of the C-peak where H is bound to C)

Offline rleung

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whoops, here's the molecule
« Reply #3 on: December 02, 2005, 06:19:34 PM »
Sorry about leaving it out the first time...

Offline Yggdrasil

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Re:C13 NMR
« Reply #4 on: December 02, 2005, 07:14:44 PM »
What kind of spectrum are you talking about?  The carbonyl carbon should show up on a regular C-NMR spectrum, but it would not show up on a DEPT spectrum, because there are no hydrogens attatched to it.

Offline Albert

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Re:C13 NMR
« Reply #5 on: December 03, 2005, 05:24:45 AM »
As you see, generally speaking, this is the spectrum you would get.
« Last Edit: December 03, 2005, 05:44:22 AM by Albert »

Offline Albert

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Re:C13 NMR
« Reply #6 on: December 03, 2005, 05:49:05 AM »
...and here is the DEPT-spectrum you probably have seen. (I agree with Yggdrasil)

Offline rleung

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Re:C13 NMR
« Reply #7 on: December 04, 2005, 02:27:51 PM »
Thanks so much.  I think the book may have been referring to a DEPT spectrum.  

Ryan

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