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Topic: Oxalic acid  (Read 8194 times)

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Offline victor

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Oxalic acid
« on: December 03, 2005, 08:04:54 AM »
anyone know what is the type of reaction (is it redox??) between:
Oxalic acid (HOOC-COOH) with Pottasium permanganate (KMnO4)? and what is the product from this reaction??
I've search it in my organic chemistry book and I find that carboxylic acid is impossible to be oxidized again....but KMnO4 itself is one of the oxydator...and the reacton is working with the color change from deep purpple to deep yellow and then continue till colorless....
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Offline Borek

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Re:Oxalic acid
« Reply #1 on: December 03, 2005, 08:22:18 AM »
« Last Edit: December 03, 2005, 09:40:40 AM by Borek »
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Beatles

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Re:Oxalic acid
« Reply #2 on: December 04, 2005, 03:46:01 AM »
Quote
(COO)22- -> 2 CO2 + 2e-

Wrong! formula of oxalate is C2O42-
« Last Edit: December 04, 2005, 03:53:10 AM by Beatles »
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Offline Alberto_Kravina

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Re:Oxalic acid
« Reply #3 on: December 04, 2005, 03:51:14 AM »
It is the same!

The oxalic acid is two carboxyl groups bound together (COOH)2. The formula of oxalate can be (COO)22- or C2O42-
   O          O
    \\       //
     C ---C
    /        \
HO          OH

The underlined H Atoms are the acidic H

Typo corrected - C2O42-, not C2H42-, Borek
« Last Edit: December 04, 2005, 06:24:14 AM by Borek »
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Beatles

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Re:Oxalic acid
« Reply #4 on: December 04, 2005, 10:00:33 AM »
Ups sorry didn't notice it's the same.
How can Borek edit alberts messages?
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Offline Borek

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Re:Oxalic acid
« Reply #5 on: December 04, 2005, 11:05:02 AM »
Quote from: Beatles on December 04, 2005, 10:00:33 AM
Ups sorry didn't notice it's the same.
How can Borek edit alberts messages?

See the sign below my name?
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Offline victor

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Re:Oxalic acid
« Reply #6 on: December 05, 2005, 08:03:16 AM »
Ok, thanks for the info....all of you really help me in making lab report... ;D
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