I found the following problem online while I was looking for steady-state approximation problems, and after I did it I found I didn't have an answer key. Could anyone tell me if my answers/thinking are correct?
Given the mechanism:
k
1PdL
2 PdL + L
k
-1 k
2PdL + ArX
PdLArX
1. Use the steady-state approximation to solve for the concentration of the intermediate
species [PdL].
2. Write the rate law for the formation of the oxidative addition product PdLArX.
We can start by realizing the rate of formation for PdL can be represented as k
1[PdL
2], and the rates of consumption as k
2[ArX][PdL] and k
-1[PdL][L].
From this, we can write d[PdL]/dt = k
1[PdL
2] - k
2[ArX][PdL] - k
-1[PdL][L] = 0, as this is the assumption for steady-state, that the concentrations of the intermediates do not change. After manipulation, [PdL] = k
1[PdL
2]/(k
2[ArX] + k
-1[L]).
For the second part, we begin by realizing that the rate of formation for PdLArX can be written as k
2[PdL][ArX]. Substituting the result in from the first part, d[PdLArX]/dt = k
1k
2[PdL
2][ArX]/(k
2[ArX] + k
-1[L]).
Thanks for your time!