December 22, 2024, 07:58:56 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: At equilibrium, but delta G doesn't = 0??  (Read 5357 times)

0 Members and 1 Guest are viewing this topic.

Offline Sophia7X

  • Full Member
  • ****
  • Posts: 248
  • Mole Snacks: +32/-4
  • Gender: Female
  • I, a universe of atoms, an atom in the universe.
At equilibrium, but delta G doesn't = 0??
« on: August 04, 2012, 11:50:04 PM »
A reaction is at equilibrium in a closed rigid vessel at constant T when...

ΔS = 0
ΔH = 0
ΔU = 0
ΔG = 0
ΔA = 0

I thought it was ΔG = 0, but it's supposed to be ΔA = 0. What is ΔA anyway? I tried googling but couldn't find what it was.
Logged
Entropy happens.

Offline Jorriss

  • Chemist
  • Full Member
  • *
  • Posts: 523
  • Mole Snacks: +41/-14
Re: At equilibrium, but delta G doesn't = 0??
« Reply #1 on: August 05, 2012, 12:55:40 AM »
deltaG=0 is the equilibrium condition at constant T and P.

In a sealed rigid container, though, the system is not at constant P so instead one must use the Helmholtz free energy, A. At constant T and V the equilibrium condition is that deltaA=0.

G=E+pV-TS and A=E-TS
Logged

Offline Sophia7X

  • Full Member
  • ****
  • Posts: 248
  • Mole Snacks: +32/-4
  • Gender: Female
  • I, a universe of atoms, an atom in the universe.
Re: At equilibrium, but delta G doesn't = 0??
« Reply #2 on: August 05, 2012, 03:23:13 PM »
Thanks
Logged
Entropy happens.
Pages: [1]   Go Up
« previous next »
Sponsored Links