Didn't think in that way
.
Okay, using your tip, 1st I saw that b) can be distinguished with the dichromate. I suppose that by CuSO
4/NaOH is meant some kind of Grignard's reagent, so it can be used for c). Now, 2 reagents and 2 pairs left and I really can't think of how they can be combined. I don't know what FeCl
3 alone can do, and first time I see iodine and NaOH together as a reagent. Maybe NaOH reacts with phenol and not with benzyl-alcohol, but why is I
2 used?