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Topic: Melting Point Lab Question  (Read 3475 times)

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Offline FabulousGal

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Melting Point Lab Question
« on: September 08, 2012, 05:38:11 PM »
The question reads:

A sample you have obtained is not completely free of solvent. What effect will this have on the observed melting point?

I am assuming that it would lower the melting point but I'm unsure. Any help would be greatly appreciated.

Offline Arkcon

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Re: Melting Point Lab Question
« Reply #1 on: September 08, 2012, 05:59:46 PM »
Can you formulate a complete answer for this question?  As in, what will the solvent actually do to lower melting point?
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Offline FabulousGal

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Re: Melting Point Lab Question
« Reply #2 on: September 08, 2012, 06:23:01 PM »
Complete answer not yet. My thinking was that any solvent left would cause the substance to be impure. In the lab we done all of the impure substances had lower melting points. I believe this would be because it is easier to break the bonds of an impure substance.

Offline Vidya

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Re: Melting Point Lab Question
« Reply #3 on: September 09, 2012, 06:09:56 AM »
You are not wrong  :)

Offline discodermolide

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Re: Melting Point Lab Question
« Reply #4 on: September 09, 2012, 06:11:48 AM »
Why should the bonds in an impure substance be easier to break? If you have I2 with some impurity in it,  the bond strength of iodine is the same in pure I2 and I2 containing the impurity.
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Offline Vidya

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Re: Melting Point Lab Question
« Reply #5 on: September 09, 2012, 06:13:59 AM »
it should not be the bonds but intermolecular forces among the molecules.

Offline FabulousGal

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Re: Melting Point Lab Question
« Reply #6 on: September 09, 2012, 08:34:20 AM »
Thank you for the help.

Offline ramboacid

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Re: Melting Point Lab Question
« Reply #7 on: September 09, 2012, 02:25:15 PM »
Pure organic compounds have a very prevalent crystal lattice structure. The pure compound thus presents a long-rage order throughout, and thus intermolecular forces that hold the crystal together are equal throughout as well. The impurities disrupt these intermolecular forces, causing some parts to melt at different temperatures and thus creates a melting point "range" that includes temperatures lower than the actual melting point.
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