[Jabean]

Hi,
I have a redox reaction which looks like the following:

In an acidic solution. I tried balancing this myself and reached the following:

However, I was told this was wrong. Can anyone shed some light on this, and if it is wrong, explain where and how to fix it?

Thanks in advance!

[Borek]

Not sure what LHO means, and what is the meaning of the arrows you have drawn, but the reaction is correctly balanced.

[Jabean]

LHO is basically charge, hydrogen count, and oxygen count. We use them for adding H⁺ and water and checking our answer. The arrows are reductions and oxidations, and that is what was wrong. After some devising, this is the final balancing:

Which still gives the same result but some different reductions/oxidations.

Thanks for the confirmation!

[Vargouille]

Your balancing is correct, but not the arrows.

Remember your half-reactions:

H2O2 + 2H⁺ + 2e^- 2H2O
2S2O3^2- S4O6^2- + 2e^-