December 27, 2024, 03:50:12 PM
Forum Rules: Read This Before Posting


Topic: Mass Balance explanation  (Read 2270 times)

0 Members and 2 Guests are viewing this topic.

Offline Marwan_Ahmed

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Mass Balance explanation
« on: September 22, 2012, 03:13:04 PM »
Hello,

Can anyone please help me with this question? I would really appreciate your help


Processes requiring SO2, often generate the feedstock by combustion of sulfur:


            S + O2 --> SO2               (1)


However, to maintain a reasonably low temperature in the burner, sufficient amounts of cool and inert gas must dilute the oxygen before it is fed to the burner.  The oxygen mixture should be about 70 mol% inert and 30 mol% oxygen.

for the inlet, how many moles would be for S, O2, N2?

I have the answers but I don't know how all the results ended to be like this. Any help please :)



Offline gensuruthebomber

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-0
Re: Mass Balance explanation
« Reply #1 on: September 23, 2012, 06:31:14 PM »
Your question looks some incomplete. SO with this data and with an arbitrary base of 1 [mol] oxigen, you will be 0,70/0,30 [mol] inert, and asuming stochiometric fedd 1 [mol] SO_2, nevertheless  I have doubts if you posted the complete problem and the level of the problem itself.

Offline fledarmus

  • Chemist
  • Sr. Member
  • *
  • Posts: 1675
  • Mole Snacks: +203/-28
Re: Mass Balance explanation
« Reply #2 on: September 24, 2012, 10:11:32 AM »
Well, the question is asking for a molar ratio. If you have 1 mole of sulfur going into the reaction, how much oxygen (moles) will you need? If that amount of oxygen is 30% of your gas mixture, how much nitrogen (moles) will you need?

Sponsored Links