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Topic: Friedel - Craft  (Read 2635 times)

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Offline perivar

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Friedel - Craft
« on: October 03, 2012, 10:14:23 AM »
Hello,

What final product would you expect in treating t - butylbenzene with an excess of 2 - chloro - 2 - methylpropane in the precens of a Aluminium chloride catalyst? At the first stages the substitution would give a para or ortho substitut, but as the reaction goes on, does all the hydrogens get substituted?
« Last Edit: October 03, 2012, 10:43:57 AM by royegilhenriksen »

Offline Babcock_Hall

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Re: Friedel - Craft
« Reply #1 on: October 03, 2012, 10:16:15 AM »
I might be missing something, but are you sure you have the correct reagents?

Offline discodermolide

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Re: Friedel - Craft
« Reply #2 on: October 03, 2012, 10:17:02 AM »
I'm not sure I would expect any product from this.
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Offline perivar

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Re: Friedel - Craft
« Reply #3 on: October 03, 2012, 10:44:58 AM »
I'm not sure I would expect any product from this.

Sorry, it should have been 2 - chloro - 2 - methylpropane

Offline discodermolide

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Re: Friedel - Craft
« Reply #4 on: October 03, 2012, 11:55:34 AM »
Alkyl groups are ortho and para directing. The ortho position may well be sterically crowded due to the t-Butyl group. So you are left with para.
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Offline NotExactly

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Re: Friedel - Craft
« Reply #5 on: October 03, 2012, 01:23:52 PM »
You'd get 1,4 di-tButyl benzene.  I think you'd get the same product even if you used 1-chloro-2-methyl propane due to carbocation rearrangement. 

Offline orgopete

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Re: Friedel - Craft
« Reply #6 on: October 04, 2012, 10:57:28 AM »
If you have an excess, a third t-butyl group also adds. This product rearranges due to steric hindrance. I believe the final product is the 1,3,5-tri-t-butylbenzene. Perhaps someone could report whether this is correct and the yield.
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