Hi all,
Working on the synthesis of Benzopinacol (and acetone) using isopropyl alcohol, benzophenone and an acetic acid catalyst in the presence of light but I cannot wrap my head around the mechanism (haven't covered in lecture yet). I have "Advanced Organic Chemistry, 5th. Structures and Mechanisms" by Carey and Sundberg and from what I read (page 1075) electron(s?) on the carbonyl of benzophenone are promoted from the HOMO orbital to the LUMO orbital giving rise to a radical. From here I'm not sure.
I've guessed that there is a donor (isopropyl alcohol) where a proton is transferred to the oxygen (radical) leaving the isopropyl alcohol with a radical at the C2 position. This is then used to generate the second equivalent of the benzophenone species allowing two benzophenol radicals to react making benzopinacol.
My guess is most likely wrong but all other reaction mechanisms I've read through SciFinder, Reaxys etc. uses a metal catalyst to donate the electron and coordinate the reaction. Also, I don't know where the acid catalyst enters the system.
Thanks in advance
Some key words that should appear in my report (don't know if this is useful):
HOMO and LUMO orbitals, Planck’s equation, ground and excited states, ultraviolet (uv) and visible light, the pyrex cut-off
for uv radiation, n -> pi* electronic transition, S0, S1, T1 descriptors of electronic states,
intersystem crossing, fluorescence, phosphorescence, dark reaction, hydrogen atom abstraction,
free radical.