The problem is:
2C
8H
18 + 25O
2 16CO
2 + 18H
2O
If 394 mol octane combusts, what volume of carbon dioxide is produced at 28.0°C and 0.995 atm?
I started by finding out how many moles of carbon dioxide are produced from the combustion of octane by doing 394 mol x (16 mol CO
2 / 2 mol C
8H
18) and got 3152 mol CO
2.
Then I did
V = nRT / P
V = (3152)(0.082)(28 + 273) / 0.0995 and I got 7.82 x 10
-4 L. But this is wrong. Can someone tell me where I went wrong?