[kapital]

Hi

I do not know exactly how to interpretate that specter.
Formula for compound is:


Specter is attched to post.

I do not know which solvent was used.

I find out this, but I am not sure it si wright:
- signal with integral 3 is from hydrogens from the final carbon of decanoil chain
- signal with integral 12,1 is from  next 6 carbons
- signal with integral 2,06 are two hydrogens from next carbon


- signal with integrals 1,97 and 1,96 are from benezne nucleus

[discodermolide]

You are doing ok at the moment. Remember that amides will show rotamers in the NMR so some signals may well be doubled.

[kapital]

Can you please tell me wich solven you think was used and which signal is from OH grop?

[discodermolide]

I don't really see a solvent signal, but I think it might be d⁶-DMSO.
The OH is sitting between the signals with integrals just before 2 and the one with 12 as a broad signal.

[Dan]

I think it might be d⁶-DMSO.

I certainly agree with DMSO. Residual solvent at 2.50 and water at 3.33.

I think the phenol OH and amide NH are the shifts around 9 ppm.

Compare 4-acetamidophenol specrum from Sigma-Aldrich.