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Technically spectrum is continuous, but it is recorded as series of points. No way to integrate other than numerically, by summation.
Solution of the Schroedinger equation is discrete, but recorded spectrum is not. Detector noise, Doppler effect and so on.
Quote from: Borek on November 20, 2012, 12:36:59 PMSolution of the Schroedinger equation is discrete, but recorded spectrum is not. Detector noise, Doppler effect and so on.Gotcha! Thanks! It's an interesting pipeline: Discrete (Schrodinger) Continuous (Noise etc.) Discrete (Measurement) Continuous (As displayed by instrument)
Quote from: curiouscat on November 20, 2012, 01:08:35 PMQuote from: Borek on November 20, 2012, 12:36:59 PMSolution of the Schroedinger equation is discrete, but recorded spectrum is not. Detector noise, Doppler effect and so on.Gotcha! Thanks! It's an interesting pipeline: Discrete (Schrodinger) Continuous (Noise etc.) Discrete (Measurement) Continuous (As displayed by instrument)If yo're interested, you should read about broadening in spectra, particularly natural lifetime and doppler broadening.