[mudkip26]

In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 23.5 oC (Celsius) are mixed in 100g of water to yield the following reaction:
NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

After mixing the temperature rises to 84 oC. Calculate the change in enthalpy of this reaction.

Specific heat of the solution = 4.184 J/(g oC)

State your answer in kJ with 3 significant figures. Don't forget to enter the unit behind the numerical answer.

The molecular weight of NaOH is 40.0 g/mol, and the molecular weight of HBr is 80.9 g/mol.
ΔH = ?

I keep doing it as such

ΔH=-(c)(m)(ΔT)

So,

ΔH=-(4.184)(100+80.9+40.0)(84-23.5)

Where am I going wrong?

[Borek]

Why do you think you are doing it wrong?

And what is the result that you got?

[mudkip26]

Why do you think you are doing it wrong?

And what is the result that you got?

I don't know where I'm going wrong.

The answer I keep getting is 54992.6132
And then divided by 101.3 is 542.8 or 543

[Borek]

Why do you think you are doing it wrong?

And what is the result that you got?

I don't know where I'm going wrong.

I don't ask where, I ask WHY do you think you are doing something wrong?

And then divided by 101.3 is 542.8 or 543

What for the division?

[mudkip26]

Why do you think you are doing it wrong?

And what is the result that you got?

I don't know where I'm going wrong.

I don't ask where, I ask WHY do you think you are doing something wrong?

And then divided by 101.3 is 542.8 or 543

What for the division?

I think I might be using the wrong equation. I'm not really sure.

I'm dividing because I'm using the equation I need it in kJ not just J

[Borek]

I think I might be using the wrong equation. I'm not really sure.

OK. So it is possible you are right?

I'm dividing because I'm using the equation I need it in kJ not just J

What is the conversion factor between J and kJ (actually between any unit and kilounit)?

[mudkip26]

I think I might be using the wrong equation. I'm not really sure.

OK. So it is possible you are right?

I'm dividing because I'm using the equation I need it in kJ not just J

What is the conversion factor between J and kJ (actually between any unit and kilounit)?

No because the online thing I am using tells me that I'm wrong.

It's 1000 J per 1 kJ correct?

[mudkip26]

I think I might be using the wrong equation. I'm not really sure.

OK. So it is possible you are right?

I'm dividing because I'm using the equation I need it in kJ not just J

What is the conversion factor between J and kJ (actually between any unit and kilounit)?

I solved it. Thank you.