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Topic: need help identifying the product  (Read 14553 times)

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Offline discodermolide

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Re: need help identifying the product
« Reply #15 on: December 10, 2012, 09:42:23 AM »
The fragment has a mass of 15 and contains 3 hydrogen atom, you know this from the hydrogen (proton) NMR.
so we have C6H5CH2O-Unknown fragment of mass 15 containing 3 hydrogen atoms.
what is this unknown fragment of mass 15 containing 3 hydrogen atoms?
Put it another way you have calculated 107 mass before, plus 3 gives 110, leaving 12!

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Offline xxdesigulxx

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Re: need help identifying the product
« Reply #16 on: December 10, 2012, 09:50:39 AM »
lithium?

Offline discodermolide

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Re: need help identifying the product
« Reply #17 on: December 10, 2012, 09:52:46 AM »
Which element has a mass of 12?
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Offline xxdesigulxx

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Re: need help identifying the product
« Reply #18 on: December 10, 2012, 09:54:05 AM »
please ignore the last comment i wrote. i wrote that earlies. Carbon has a mass of 12

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Re: need help identifying the product
« Reply #19 on: December 10, 2012, 09:55:54 AM »
Right,
so we now have
C6H5CH2-O-CH3, (methoxymethyl)benzene is your unknown.
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Offline xxdesigulxx

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Re: need help identifying the product
« Reply #20 on: December 10, 2012, 10:07:49 AM »
omg thank you so much. It is same as methoxytoluene right? and am i missing something from the IR Spectrum? meaning did i name the functional groups right beside the alcohol?

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Re: need help identifying the product
« Reply #21 on: December 10, 2012, 10:11:07 AM »
The IR does not really tell you much apart from the presence of an aromatic C=C. apart from the OH mistake it's ok.
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Offline xxdesigulxx

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Re: need help identifying the product
« Reply #22 on: December 10, 2012, 10:14:05 AM »
thank you so much for your help.

Offline discodermolide

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Re: need help identifying the product
« Reply #23 on: December 10, 2012, 10:14:33 AM »
My pleasure.
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Offline orgopete

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Re: need help identifying the product
« Reply #24 on: December 10, 2012, 10:35:06 AM »
The IR does not really tell you much apart from the presence of an aromatic C=C. apart from the OH mistake it's ok.


I do not conclude the IR shows an OH group is present. It is valuable to compare actual spectra with different functional groups to help estimate the magnitude of absorptions. The OH band is rather small compared to the relatively weak CH bands. Overtones and water can give weak absorptions. If an alcohol were present, you would find an OH band is much stronger than than even multiple CH absorptions.
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Offline discodermolide

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Re: need help identifying the product
« Reply #25 on: December 10, 2012, 10:44:59 AM »
Orgopete, did you actually read the entire post? Replies 3 & 4 especially, number 3, from the OP said there was an OH present, number 4, I corrected him and said there was no OH.

So I don't really understand your comment.
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Offline orgopete

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Re: need help identifying the product
« Reply #26 on: December 10, 2012, 03:07:10 PM »
Orgopete, did you actually read the entire post? Replies 3 & 4 especially, number 3, from the OP said there was an OH present, number 4, I corrected him and said there was no OH.

So I don't really understand your comment.

Yes, and I looked at the spectrum. The poster also looked at the spectrum and had concluded the weak band around 3300 cm-1 Indicated an OH. Could both be correct? I presumed the poster was inexperienced and thought the weak peak could have been an OH. My comment was directed to that audience to help them distinguish between an alcohol and the instance in which the some environmental OH or even an overtone of a carbonyl compound could leave a small and weak peak in the OH region.

Please check the spectrum yourself and tell us if the poster mistakenly reported the wrong frequency.
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Re: need help identifying the product
« Reply #27 on: December 10, 2012, 03:29:36 PM »
Thank you for the clarification, it was not clear to whom you were addressing the comment.
The very small peak in the IR which the poster recorded as being between 3400-3500 cm-1is very likely traces of water, certainly not an alcohol, which is much more intense. Certainly the OH stretch lies within this region.
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