[Tittywahah]

I have searched and searched, but I can not discover how I get rid of the Hydrogen in the Sodium Bisulphite.  Perhaps someone could open a door to some chemistry that would have helped me to figure this out.

[Wastrel]

Sodium Bisulphite is Sodium Hydrogen Sulphite, it's acidic, so if you add Sodium Hydroxide it will form the neutral salt.

[Tittywahah]

Sodium Bisulphite is Sodium Hydrogen Sulphite, it's acidic, so if you add Sodium Hydroxide it will form the neutral salt.

Ok Thankyou: NaHSO3+NaOH=Na2SO3+H2O  Since I am starting with Sodium Metabisulphite, add this to water it splits into two Bisulphites which would then be , according to my amateur logic of chemistry still, as follows:
The Bisulphite is 104 g/mol   The Sulphite is 126 g/mol
If I have two Bisulphite ions in the water this would then be 208 g/mol
So I presume then that I would have to add 2 moles of NaOH.

So the reaction would be: 2NaHSO3+2NaOH since I have to take into consideration the two bisulphites that were a result of the metabisulphite that was originally added to the water?  Have I thought this out correctly?

[Wastrel]

Yes, you would need 80g (2 moles) of NaOH per 190g (1 mole) of sodium metabisulphite.

[Tittywahah]

Yes, you would need 80g (2 moles) of NaOH per 190g (1 mole) of sodium metabisulphite.

Forgot to say thankyou.